Step 1: Formula for refractive index.
The refractive index \( n \) is given by the formula:
\[
n = \frac{c}{v}
\]
where:
- \( c = 3 \times 10^{10} \, \text{m/s} \) (speed of light in vacuum),
- \( v = 200 \times 10^8 \, \text{cm/s} = 2 \times 10^{9} \, \text{m/s} \) (speed of light in the medium).
Step 2: Calculate the refractive index.
Substituting the values:
\[
n = \frac{3 \times 10^{10}}{2 \times 10^9} = 1.5
\]
Step 3: Conclusion.
Thus, the refractive index for this medium is 1.5, so the correct answer is (B).