If the speed of a moving particle is decreased by 1%, the de Broglie wavelength of the wave associated with it
decreases by 1%
increases by 1%
decreases by 2%
increases by 2%
decreases by 5%
Step 1: The de Broglie wavelength \(\lambda\) of a particle is given by \(\lambda = \frac{h}{mv}\), where \(h\) is Planck's constant, \(m\) is the mass, and \(v\) is the velocity of the particle.
Step 2: A decrease in speed by 1% implies \(v' = 0.99v\).
Step 3: The new wavelength \(\lambda'\) becomes \(\lambda' = \frac{h}{m \cdot 0.99v} = \frac{1}{0.99} \lambda \approx 1.01 \lambda\).
Step 4: Thus, the de Broglie wavelength increases by approximately 1%.