If the speed of a moving particle is decreased by 1%, the de Broglie wavelength of the wave associated with it
decreases by 1%
increases by 1%
decreases by 2%
increases by 2%
decreases by 5%
Step 1: The de Broglie wavelength \(\lambda\) of a particle is given by \(\lambda = \frac{h}{mv}\), where \(h\) is Planck's constant, \(m\) is the mass, and \(v\) is the velocity of the particle.
Step 2: A decrease in speed by 1% implies \(v' = 0.99v\).
Step 3: The new wavelength \(\lambda'\) becomes \(\lambda' = \frac{h}{m \cdot 0.99v} = \frac{1}{0.99} \lambda \approx 1.01 \lambda\).
Step 4: Thus, the de Broglie wavelength increases by approximately 1%.
A cube of side 10 cm is suspended from one end of a fine string of length 27 cm, and a mass of 200 grams is connected to the other end of the string. When the cube is half immersed in water, the system remains in balance. Find the density of the cube.