Question:

If the roots of the equation $x^2 + 2ax + b = 0$ are real and distinct and they differ by at most $2m$, then $b$ lies in the interval

Updated On: Jul 6, 2022
  • $(a^2 - m^{2-}, a^2)$
  • $[a^2 - m^2, a^2]$
  • $[a^2, a^2 + m^2]$
  • none of these
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Let $\alpha,\, \beta $ be the roots of $x^2 + 2\,ax + b = 0 \,\,\,\,...(1)$ $\therefore \, \alpha + \beta = - 2\,a$ and $\alpha \, \beta = b$ By the given condition $|\alpha - \beta| \leq \, 2m$ $\therefore \, (\alpha - \beta)^2 \leq 4m^2$ $\Rightarrow (\alpha + \beta)^2 - 4 \, \alpha \, \beta \leq 4m^2$
Was this answer helpful?
0
0

Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.