Step 1: Recall the property of similar triangles.
In two similar triangles, the ratio of any corresponding linear dimensions (such as sides, altitudes, medians, or angle bisectors) is the same as the ratio of their corresponding sides.
Step 2: Apply the property to the altitudes.
Since the ratio of the corresponding sides of the two triangles is \( 2 : 3 \), the ratio of their corresponding altitudes will also be \( 2 : 3 \).
Final Answer: The ratio of the corresponding altitudes is \( \mathbf{2 : 3} \), which corresponds to option \( \mathbf{(3)} \).
In the adjoining figure, \( \triangle CAB \) is a right triangle, right angled at A and \( AD \perp BC \). Prove that \( \triangle ADB \sim \triangle CDA \). Further, if \( BC = 10 \text{ cm} \) and \( CD = 2 \text{ cm} \), find the length of } \( AD \).
If a line drawn parallel to one side of a triangle intersecting the other two sides in distinct points divides the two sides in the same ratio, then it is parallel to the third side. State and prove the converse of the above statement.
In the adjoining figure, \( AP = 1 \, \text{cm}, \ BP = 2 \, \text{cm}, \ AQ = 1.5 \, \text{cm}, \ AC = 4.5 \, \text{cm} \) Prove that \( \triangle APQ \sim \triangle ABC \).
Hence, find the length of \( PQ \), if \( BC = 3.6 \, \text{cm} \).