$2 : 1$
Step 1: The intensity of a wave is proportional to the square of its amplitude: \[ I \propto A^2 \]
Step 2: Given that the amplitude ratio is $2:1$, let $A_1 = 2A$ and $A_2 = A$.
Step 3: The intensity ratio is: \[ I_1 : I_2 = (2A)^2 : (A)^2 \] \[ = 4A^2 : A^2 = 4 : 1 \]
Step 4: Therefore, the correct answer is (A).
In Young’s double slit experiment, to change the bandwidth from $\beta$ to $\frac{\beta}{4}$ without changing the experimental setup, the wavelength of light $\lambda$ used must be changed to