Question:
If the radius of the earth were to shrink by one per cent, its mass remaining the same, the value of \(g\) on the earth's surface would
If the radius of the earth were to shrink by one per cent, its mass remaining the same, the value of \(g\) on the earth's surface would
Updated On: Apr 23, 2024
- increase by 0.5%
- increase by 2%
- decrease by 0.5%
- decrease by 2%
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The Correct Option is B
Solution and Explanation
$g = \frac{GM}{R^{2}} \Rightarrow \frac{dg}{g} = - 2 \frac{dR}{R} $
$ \frac{dR}{R}= - 1 \% \Rightarrow \frac{dg}{g} =2 \%$
$ \frac{dR}{R}= - 1 \% \Rightarrow \frac{dg}{g} =2 \%$
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Concepts Used:
Acceleration
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
