Question:

If the product of zeroes of the polynomial \( ax^2 - 6x - 6 \) is 4, find the value of 'a'

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For quadratic equations, the product of the roots is \( \frac{c}{a} \), which helps in solving for coefficients.
Updated On: Aug 18, 2025
  • -3/2
  • -1/2
  • 3/2
  • 1/2
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The Correct Option is A

Solution and Explanation

For a quadratic equation \( ax^2 + bx + c = 0 \), the product of its roots is given by \( \frac{c}{a} \). Here, the equation is \( ax^2 - 6x - 6 = 0 \), so the product of the roots is: \[ \text{Product of zeroes} = \frac{c}{a} = \frac{-6}{a} \] According to the problem, the product of the zeroes is 4, so: \[ \frac{-6}{a} = 4 \] Solving for \( a \): \[ a = -\frac{6}{4} = -\frac{3}{2} \]
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