The power \( P \) of a lens is related to its focal length \( f \) by the equation: \[ P = \frac{1}{f} \] where: - \( P \) is the power of the lens in diopters (D),
- \( f \) is the focal length of the lens in meters.
We are given that the power of the lens is \( P = -2.0 \, {D} \).
The negative sign indicates that the lens is a concave lens (since concave lenses have negative focal lengths).
Using the formula for power: \[ P = \frac{1}{f} \] Substitute the value of \( P \): \[ -2.0 = \frac{1}{f} \] Solving for \( f \): \[ f = \frac{1}{-2.0} = -0.5 \, {m} = -50 \, {cm} \] Thus, the focal length of the lens is \( -50 \, {cm} \), and since the focal length is negative, the lens is a concave lens.
Therefore, the correct answer is: \[ \boxed{{B) Concave lens, 50 cm}} \]
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: