If the potential energy of a particle of mass \(0.1 \, \text{kg}\) moving along the x-axis is \(5x(x - 4)\), then the speed of the particle is maximum at a position of:
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For a particle moving under a potential, the speed is maximum when the force acting on the particle is zero. This can be found by setting the derivative of the potential to zero.
The potential energy \(U(x)\) is given as:
\[
U(x) = 5x(x - 4).
\]
The force \(F(x)\) is the negative gradient of the potential energy:
\[
F(x) = - \frac{dU}{dx} = - \frac{d}{dx} \left( 5x(x - 4) \right).
\]
Calculating the derivative:
\[
F(x) = -5 \left( 2x - 4 \right) = -10(x - 2).
\]
The speed of the particle is maximum where the force is zero, which occurs at \(x = 3 \, \text{m}\).