Step 1: Understanding the 10-bit radiometric resolution.
In a 10-bit image, the number of possible Digital Numbers (DNs) ranges from 0 to \(2^{10} - 1\). This is because a 10-bit resolution allows for 1024 distinct values, which range from 0 to 1023.
Step 2: Determining the maximum DN value.
The maximum DN value is equal to \(2^{10} - 1\), which is: \[ 2^{10} - 1 = 1024 - 1 = 1023 \] Therefore, the maximum DN value of the image is \(1023\).
The error matrix resulting from randomly selected test pixels for a classified image is given below.
The Producer’s accuracy of class 1 is % (rounded off to 1 decimal place).
Reference Data | |||||
---|---|---|---|---|---|
Class 1 | Class 2 | Class 3 | Class 4 | ||
Classified Data | Class 1 | 320 | 8 | 7 | 3 |
Class 2 | 12 | 270 | 6 | 2 | |
Class 3 | 9 | 6 | 410 | 5 | |
Class 4 | 14 | 2 | 3 | 350 |
The brightness values of four pixels in the input image are shown in the table below. The image is rectified using nearest neighbor intensity interpolation, and the pixel at location (5, 4) in the output image is to be filled with the value from coordinate (5.3, 3.7) in the input image. The brightness value of the pixel at location (5, 4) in the rectified output image is 11. (Answer in integer)
Location of pixels in input image (Row, Column) | Brightness Value |
---|---|
(5, 3) | 9 |
(5, 4) | 11 |
(6, 3) | 14 |
(6, 4) | 12 |
A 4 × 4 digital image has pixel intensities (U) as shown in the figure. The number of pixels with \( U \leq 4 \) is:
The following table provides the mineral chemistry of a garnet. All oxides are in weight percentage and cations in atoms per formula unit. Total oxygen is taken as 12 based on the ideal garnet formula. Consider Fe as Fetotal and Fe\(^{3+}\) = 0. The Xpyrope of this garnet is _.
In the isochemical phase diagram shown below, the curved arrow represents the P-T path. The variance at peak metamorphism is _.
A sediment core of 4 cm diameter and 35.81 cm height was collected. This core had an initial weight of 1000.00 g and upon drying the sediment, the weight decreased by 133.75 g. This core has a void ratio of 0.42857, where void ratio is defined as the ratio of volume of void to the volume of solid (Vv/Vs). The average density of the sediment in the core is ________ g/cm\(^3\).