Question:
If the line \(2x+\sqrt6y=2\) touches the hyperbola x2 - 2y2 = 4, then the point of contact is
If the line \(2x+\sqrt6y=2\) touches the hyperbola x2 - 2y2 = 4, then the point of contact is
Updated On: Sep 15, 2024
- \((-4,\sqrt6)\)
- \((-4,-\sqrt6)\)
- \((4,-\sqrt6)\)
- \((4,\sqrt6)\)
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The Correct Option is C
Solution and Explanation
The correct option is (C) : \((4,-\sqrt6)\).
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