Given:
Length of shadow of a tower = \(\sqrt{3}\) times its height.
Step 1: Let the height of tower = \(h\)
Length of shadow = \(\sqrt{3} \, h\)
Step 2: Use right triangle trigonometry
The angle of elevation of the sun is \(\theta\).
\[
\tan \theta = \frac{\text{height}}{\text{shadow}} = \frac{h}{\sqrt{3} \, h} = \frac{1}{\sqrt{3}}
\]
Step 3: Find \(\theta\) from \(\tan \theta = \frac{1}{\sqrt{3}}\)
\[
\tan 30^\circ = \frac{1}{\sqrt{3}}
\]
So,
\[
\theta = 30^\circ
\]
Final Answer:
\[
\boxed{30^\circ}
\]