Question

If the horizontal range of a body projected with a velocity \(u\) is 3 times the maximum height reached by it, then the range of the body is:

• A. \(\frac{2u^2}{3g}\)
• B. \(\frac{4u^2}{5g}\)
• C. \(\frac{12u^2}{13g}\)
• D. \(\frac{24u^2}{25g}\)

Hint:

Use the relations for range and maximum height in projectile motion to find the unknowns.

Answer 1

The Correct Option is A

Using the relation for horizontal range \(R = \frac{u^2 \sin(2\theta)}{g}\) and maximum height \(H = \frac{u^2 \sin^2(\theta)}{2g}\), and knowing that \(R = 3H\), we find: \[ R = \frac{2u^2}{3g}. \]