Question:

If the height of a pole is \( 2\sqrt{3} \) metres and the length of its shadow is 2 metres, what is the angle of elevation of the sun?

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Use \(\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}\) when height and shadow length are given to find angle of elevation.
  • \( 60^\circ \)
  • \( 45^\circ \)
  • \( 30^\circ \)
  • \( 15^\circ \)
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The Correct Option is A

Solution and Explanation

Step 1: Use the definition of tangent in a right triangle.
Let \( \theta \) be the angle of elevation of the sun. We have: \[ \tan(\theta) = \frac{\text{Height of pole}}{\text{Length of shadow}} = \frac{2\sqrt{3}}{2} = \sqrt{3} \] Step 2: Use trigonometric value.
We know that: \[ \tan(60^\circ) = \sqrt{3} \] So, \( \theta = 60^\circ \)
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