Step 1: Use the definition of tangent in a right triangle.
Let \( \theta \) be the angle of elevation of the sun.
We have:
\[
\tan(\theta) = \frac{\text{Height of pole}}{\text{Length of shadow}} = \frac{2\sqrt{3}}{2} = \sqrt{3}
\]
Step 2: Use trigonometric value.
We know that:
\[
\tan(60^\circ) = \sqrt{3}
\]
So, \( \theta = 60^\circ \)