Question:

If the errors in the measurement of the mass and side of a cubical block are 2% and 1% respectively, then the error in the determination of the density of the material of the block is

Show Hint

When calculating the error in derived quantities, use the formula for relative error propagation. For density, the error in volume (cube) contributes three times the error in the side length.
Updated On: Mar 15, 2025
  • 8%
  • 6%
  • 3%
  • 5%
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The density ρ \rho of a cubical block is given by: ρ=massvolume=ma3 \rho = \frac{{mass}}{{volume}} = \frac{m}{a^3} where m m is the mass and a a is the side length of the cube. The relative error in density is given by: Δρρ=Δmm+3Δaa \frac{\Delta \rho}{\rho} = \frac{\Delta m}{m} + 3 \cdot \frac{\Delta a}{a} Given: 
Error in mass Δmm=2 \frac{\Delta m}{m} = 2%  
Error in side length Δaa=1 \frac{\Delta a}{a} = 1%
Substituting the values: Δρρ=2 \frac{\Delta \rho}{\rho} = 2% + 3 \cdot 1% = 2% + 3% = 5% Thus, the error in the determination of the density is 5%.
Final Answer:  5% 
 

Was this answer helpful?
0
0