Question:

If the equation \(x^4 + 7x^3 + 18x^2 + 20x + 8 = 0\) has a repeated root, then that repeated root is:

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To find repeated roots, check which root is common between the polynomial and its derivative.
Updated On: May 15, 2025
  • \( \mathbf{-2} \)
  • \( -1 \)
  • \( -3 \)
  • \( -4 \)
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The Correct Option is A

Solution and Explanation

Let \( f(x) = x^4 + 7x^3 + 18x^2 + 20x + 8 \). Since the polynomial has a repeated root, it must be a common root of \( f(x) \) and \( f'(x) \). Compute derivative: \[ f'(x) = 4x^3 + 21x^2 + 36x + 20 \] Use Euclidean algorithm or factorization approach. Try rational root theorem: test \( x = -2 \): \[ f(-2) = 16 - 56 + 72 - 40 + 8 = 0 \Rightarrow \text{So } x = -2 \text{ is a root} \] Now check if it’s repeated: \[ f'(-2) = -32 + 84 - 72 + 20 = 0 \Rightarrow \text{So } x = -2 \text{ is also a root of } f'(x) \] Hence, \( x = -2 \) is a repeated root.
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