Question:

If the Earth were to suddenly contract to $\frac{1}{n}$ th of its present radius without any change in its mass, the duration of the new day will be nearly

Updated On: Feb 15, 2024
  • $24/n\, hr$
  • $24\,n\, hr$
  • $24/n^2\, hr$
  • $24\, n^2\, hr$
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The Correct Option is C

Solution and Explanation

From the conservation of momentum, we have
$I_{1} \omega_{1}=I_{2} \omega_{2}$
Thus, we get $\frac{2}{5} M R^{2}\left(\frac{2 \pi}{T_{1}}\right)$
$=\frac{2}{5} M \frac{R^{2}}{n^{2}}\left(\frac{2 \pi}{T_{2}}\right)$
Hence, we get $T_{2}=\frac{T_{1}}{n^{2}}=\frac{24}{n^{2}} h$
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.