Question:

If the direction cosines of a line are \(\dfrac{4}{\sqrt{77}},\ \dfrac{5}{\sqrt{77}},\ \dfrac{x}{\sqrt{77}}\), then the value of \(x\) is

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Direction cosines are the components of a unit direction vector, so they always satisfy \(l^2+m^2+n^2=1\).
  • \(6\)
  • \(7\)
  • \(8\)
  • \(9\)
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The Correct Option is A

Solution and Explanation

For any line in 3-D, its direction cosines \(l,m,n\) satisfy \[ l^{2}+m^{2}+n^{2}=1 \text{(unit vector condition).} \] Here \(l=\dfrac{4}{\sqrt{77}},\ m=\dfrac{5}{\sqrt{77}},\ n=\dfrac{x}{\sqrt{77}}\). So \[ \left(\frac{4}{\sqrt{77}}\right)^{2}+\left(\frac{5}{\sqrt{77}}\right)^{2}+\left(\frac{x}{\sqrt{77}}\right)^{2}=1 \] \[ \frac{16+25+x^{2}}{77}=1 \ \Rightarrow\ 16+25+x^{2}=77\ \Rightarrow\ x^{2}=36. \] Hence \(x=\pm 6\). Among the choices the matching value is \(6\).
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