If the coordinates of the points A and B are (3, 3) and (7, 6), then the length of the portion of the line AB intercepted between the axes is:
We are given two points: \( A(3, 3) \) and \( B(7, 6) \). We need to find the length of the portion of the line AB intercepted between the axes.
First, find the equation of the line passing through points \( A(3, 3) \) and \( B(7, 6) \). The slope of the line is: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 - 3}{7 - 3} = \frac{3}{4}. \] Now, use the point-slope form of the line equation: \[ y - y_1 = m(x - x_1). \] Using point \( A(3, 3) \): \[ y - 3 = \frac{3}{4}(x - 3). \] Simplifying: \[ y - 3 = \frac{3}{4}x - \frac{9}{4} \quad \Rightarrow \quad y = \frac{3}{4}x - \frac{9}{4} + 3 = \frac{3}{4}x + \frac{3}{4}. \] Thus, the equation of the line is: \[ y = \frac{3}{4}x + \frac{3}{4}. \] Next, find the intercepts of the line with the axes: - For the \( x \)-intercept, set \( y = 0 \): \[ 0 = \frac{3}{4}x + \frac{3}{4} \quad \Rightarrow \quad x = -1. \] Thus, the \( x \)-intercept is \( (-1, 0) \). - For the \( y \)-intercept, set \( x = 0 \): \[ y = \frac{3}{4}(0) + \frac{3}{4} = \frac{3}{4}. \] Thus, the \( y \)-intercept is \( (0, \frac{3}{4}) \). Now, use the distance formula to find the length of the segment between the intercepts \( (-1, 0) \) and \( (0, \frac{3}{4}) \): \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(0 - (-1))^2 + \left(\frac{3}{4} - 0\right)^2}. \] Simplifying: \[ d = \sqrt{1^2 + \left(\frac{3}{4}\right)^2} = \sqrt{1 + \frac{9}{16}} = \sqrt{\frac{16}{16} + \frac{9}{16}} = \sqrt{\frac{25}{16}} = \frac{5}{4}. \] Thus, the length of the portion of the line AB intercepted between the axes is \( \frac{5}{4} \).
Let $C$ be the circle $x^2 + (y - 1)^2 = 2$, $E_1$ and $E_2$ be two ellipses whose centres lie at the origin and major axes lie on the $x$-axis and $y$-axis respectively. Let the straight line $x + y = 3$ touch the curves $C$, $E_1$, and $E_2$ at $P(x_1, y_1)$, $Q(x_2, y_2)$, and $R(x_3, y_3)$ respectively. Given that $P$ is the mid-point of the line segment $QR$ and $PQ = \frac{2\sqrt{2}}{3}$, the value of $9(x_1 y_1 + x_2 y_2 + x_3 y_3)$ is equal to
In the given cycle ABCDA, the heat required for an ideal monoatomic gas will be:
A conducting wire is stretched by applying a deforming force, so that its diameter decreases to 40% of the original value. The percentage change in its resistance will be: