Step 1: Analyze the acceleration-time diagram.
Given that the acceleration-time diagram is a horizontal straight line, this means that the acceleration is constant over time. Mathematically, acceleration \( a(t) \) can be expressed as a constant value \( a_0 \). Thus,
\[
a(t) = a_0 \quad \text{(constant acceleration)}.
\]
Step 2: Determine the velocity-time relationship.
The velocity is the integral of acceleration with respect to time:
\[
v(t) = \int a(t) \, dt = \int a_0 \, dt = a_0 t + v_0,
\]
where \( v_0 \) is the initial velocity. This gives a linear relationship between velocity and time, meaning the velocity-time diagram is a straight line with slope \( a_0 \).
Step 3: Determine the displacement-time relationship.
The displacement is the integral of velocity with respect to time:
\[
s(t) = \int v(t) \, dt = \int (a_0 t + v_0) \, dt = \frac{1}{2} a_0 t^2 + v_0 t + s_0,
\]
where \( s_0 \) is the initial displacement. This equation represents a parabolic curve in the displacement-time diagram. The displacement-time graph is a parabola because the second derivative of the displacement is constant acceleration.
Conclusion:
Therefore, when the acceleration is constant, the displacement follows a parabolic curve.
Final Answer: The displacement is a parabolic curve.