Question

If the absolute temperature (greater than 0 K) of a body is doubled, it would emit \underline{{2cm} times more radiation.}

• A. \( {2} \)
• B. \( {4} \)
• C. \( {8} \)
• D. \( {16} \)

Hint:

Remember the Stefan–Boltzmann law: \( E \propto T^4 \). Doubling the absolute temperature leads to \( 2^4 = 16 \) times more radiated energy. This is a commonly tested concept in thermal remote sensing and physics.

Answer 1

The Correct Option is D

The amount of radiation emitted by a blackbody is given by the Stefan–Boltzmann law, which states: \[ E = \sigma T^4 \] where \( E \) is the emissive power, \( \sigma \) is the Stefan–Boltzmann constant, and \( T \) is the absolute temperature in Kelvin. If the temperature is doubled: \[ E' = \sigma (2T)^4 = \sigma \cdot 16T^4 = 16E \] This means the body will emit 16 times more radiation.