Question:

If percentage of N$_2$ above a liquid solution is 80% at a total pressure of 10 atm, then find the mole fraction of N$_2$ gas dissolved in solution.
[Given that Henry’s constant for N$_2$ is $7.6 \times 10^7$ mm Hg]

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Always convert pressure into the same unit as Henry’s constant before substitution.
Updated On: Jan 25, 2026
  • $10^{-4}$
  • $8 \times 10^{-5}$
  • $10^{-7}$
  • $10^{-6}$
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The Correct Option is B

Solution and Explanation

Step 1: Apply Henry’s law.
According to Henry’s law:
\[ P_{N_2} = K_H X_{N_2} \]
Step 2: Calculate partial pressure of N$_2$.
Given that percentage of N$_2$ is 80% and total pressure is 10 atm:
\[ P_{N_2} = 0.8 \times 10 = 8\ \text{atm} \]
Step 3: Convert pressure into mm Hg.
\[ 8\ \text{atm} = 8 \times 760 = 6080\ \text{mm Hg} \]
Step 4: Calculate mole fraction of N$_2$.
\[ X_{N_2} = \frac{P_{N_2}}{K_H} = \frac{6080}{7.6 \times 10^7} \] \[ X_{N_2} = 8 \times 10^{-5} \]
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