Given the probabilities:
\[ P(A) = P(B) = \frac{5}{13}, \quad P(A \cap B) = \frac{2}{5}, \] we need to find \( P(A \cup B) \).
Using the formula for the union of two events, we have:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Substituting the given values: \[ P(A \cup B) = \frac{5}{13} + \frac{5}{13} - \frac{2}{5} \]
Now, simplify:
\[ P(A \cup B) = \frac{10}{13} - \frac{2}{5} \] To subtract these fractions, find a common denominator (the LCM of 13 and 5 is 65): \[ P(A \cup B) = \frac{50}{65} - \frac{26}{65} = \frac{24}{65} \]
\[ P(A \cup B) = \frac{24}{65} \]
If A and B are two events such that \( P(A \cap B) = 0.1 \), and \( P(A|B) \) and \( P(B|A) \) are the roots of the equation \( 12x^2 - 7x + 1 = 0 \), then the value of \(\frac{P(A \cup B)}{P(A \cap B)}\)
A quadratic polynomial \( (x - \alpha)(x - \beta) \) over complex numbers is said to be square invariant if \[ (x - \alpha)(x - \beta) = (x - \alpha^2)(x - \beta^2). \] Suppose from the set of all square invariant quadratic polynomials we choose one at random. The probability that the roots of the chosen polynomial are equal is ___________. (rounded off to one decimal place)