If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4, find:
\((i)\) \(P(A∩B) = P(B|A).P(A)\)
\(P(A∩B = 0.4\times0.8\)
\(P(A∩B) = 0.3\)
\((ii)\) \(P(A|B)=\frac {P(A∩B)}{P(B)}\)
\(P(A|B)=\frac {0.32}{0.50}\)
\(P(A|B)=\frac {32}{50}\)
\(P(A|B)=0.64\)
\((iii)\) \(P(A∪B)=P(A)+P(B)-P(A∩B)\)
\(P(A∪B)=0.8+0.5 – 0.32\)
\(P(A∪B)= 0.98\)

Rishika and Shivika were partners in a firm sharing profits and losses in the ratio of 3 : 2. Their Balance Sheet as at 31st March, 2024 stood as follows:
Balance Sheet of Rishika and Shivika as at 31st March, 2024
| Liabilities | Amount (₹) | Assets | Amount (₹) |
|---|---|---|---|
| Capitals: | Equipment | 45,00,000 | |
| Rishika – ₹30,00,000 Shivika – ₹20,00,000 | 50,00,000 | Investments | 5,00,000 |
| Shivika’s Husband’s Loan | 5,00,000 | Debtors | 35,00,000 |
| Creditors | 40,00,000 | Stock | 8,00,000 |
| Cash at Bank | 2,00,000 | ||
| Total | 95,00,000 | Total | 95,00,000 |
The firm was dissolved on the above date and the following transactions took place:
(i) Equipements were given to creditors in full settlement of their account.
(ii) Investments were sold at a profit of 20% on its book value.
(iii) Full amount was collected from debtors.
(iv) Stock was taken over by Rishika at 50% discount.
(v) Actual expenses of realisation amounted to ₹ 2,00,000 which were paid by the firm. Prepare Realisation Account.
Conditional Probability is defined as the occurrence of any event which determines the probability of happening of the other events. Let us imagine a situation, a company allows two days’ holidays in a week apart from Sunday. If Saturday is considered as a holiday, then what would be the probability of Tuesday being considered a holiday as well? To find this out, we use the term Conditional Probability.
P(S | B) = P(B | B) = 1.
Proof of the same: P(S | B) = P(S ∩ B) ⁄ P(B) = P(B) ⁄ P(B) = 1.
[S ∩ B indicates the outcomes common in S and B equals the outcomes in B].
P(B | A), P(A) >0 or, P(A ∩ B) = P(B).P(A | B), P(B) > 0.
This theorem is named as the Multiplication Theorem of Probability.
Proof of the same: As we all know that P(B | A) = P(B ∩ A) / P(A), P(A) ≠ 0.
We can also say that P(B|A) = P(A ∩ B) ⁄ P(A) (as A ∩ B = B ∩ A).
So, P(A ∩ B) = P(A). P(B | A).
Similarly, P(A ∩ B) = P(B). P(A | B).
The interesting information regarding the Multiplication Theorem is that it can further be extended to more than two events and not just limited to the two events. So, one can also use this theorem to find out the conditional probability in terms of A, B, or C.
Read More: Types of Sets
Sometimes students get confused between Conditional Probability and Joint Probability. It is essential to know the differences between the two.