Step 1: Understanding pH.
The pH scale is logarithmic and measures the concentration of hydrogen ions \([H^+]\). The formula for pH is: \[ {pH} = -\log[H^+] \] Thus, a solution with pH 7 has a hydrogen ion concentration of \([H^+] = 10^{-7}\) mol/L, and a solution with pH 6 has \([H^+] = 10^{-6}\) mol/L.
Step 2: Mixing the two solutions.
When two solutions are mixed, the resulting concentration of \([H^+]\) is the average of the two concentrations, as the volumes are equal. The combined concentration of hydrogen ions is: \[ [H^+]_{{mix}} = \frac{(10^{-7} + 10^{-6})}{2} = \frac{1.1 \times 10^{-6}}{2} = 5.5 \times 10^{-7} \] Step 3: Calculating the resulting pH.
Now, we calculate the pH of the resulting solution: \[ {pH}_{{mix}} = -\log(5.5 \times 10^{-7}) = 6.26 \] Therefore, the resulting pH of the mixture is approximately \(6.26\).
The following table provides the mineral chemistry of a garnet. All oxides are in weight percentage and cations in atoms per formula unit. Total oxygen is taken as 12 based on the ideal garnet formula. Consider Fe as Fetotal and Fe\(^{3+}\) = 0. The Xpyrope of this garnet is _.
In the isochemical phase diagram shown below, the curved arrow represents the P-T path. The variance at peak metamorphism is _.
A sediment core of 4 cm diameter and 35.81 cm height was collected. This core had an initial weight of 1000.00 g and upon drying the sediment, the weight decreased by 133.75 g. This core has a void ratio of 0.42857, where void ratio is defined as the ratio of volume of void to the volume of solid (Vv/Vs). The average density of the sediment in the core is ________ g/cm\(^3\).