We are given that \( n^3 \) is odd. Let's analyze the statements one by one:
1. Statement I: \( n \) is odd.
- If \( n^3 \) is odd, then \( n \) must be odd. This is because the cube of an even number is always even. Hence, for \( n^3 \) to be odd, \( n \) must be odd.
- Statement I is true.
2. Statement II: \( n^2 \) is odd.
- If \( n \) is odd, then \( n^2 \) will also be odd. This is because the square of an odd number is always odd. Thus, \( n^2 \) is indeed odd if \( n \) is odd.
- Statement II is true.
3. Statement III: \( n^2 \) is even.
- This contradicts statement II. If \( n \) is odd, \( n^2 \) cannot be even. Therefore, statement III is false.
- Statement III is false.
Thus, the correct answer is Option 3: I and II.