To solve the problem, we need to find the median using the given values of mode and mean.
1. Recall the Empirical Relationship:
There is an empirical relationship between mean, median, and mode for a moderately skewed distribution:
$ \text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean} $
2. Substituting the Known Values:
Mode = 29, Mean = 32
Using the formula:
$ 29 = 3 \times \text{Median} - 2 \times 32 $
$ 29 = 3 \times \text{Median} - 64 $
3. Solving for Median:
$ 29 + 64 = 3 \times \text{Median} $
$ 93 = 3 \times \text{Median} $
$ \text{Median} = \frac{93}{3} = 31 $
Final Answer:
The median is $ {31} $
Find the mean and mode of the following data:
Class | 15--20 | 20--25 | 25--30 | 30--35 | 35--40 | 40--45 |
Frequency | 12 | 10 | 15 | 11 | 7 | 5 |