If $\log_2 (x) + \log_4 (x) = 5$, what is $x$?
210/2
210/3
211/3
210/7
Recall the base change formula:
log4(x) = log2(x) / log2(4)
Since log2(4) = 2, we get:
log4(x) = log2(x) / 2
Substituting into the original equation:
log2(x) + (log2(x) / 2) = 5
Let y = log2(x):
y + y/2 = 5
(3y / 2) = 5
3y = 10
y = 10/3
Since y = log2(x):
log2(x) = 10/3
x = 210/3
x = 210/3
The product of all solutions of the equation \(e^{5(\log_e x)^2 + 3 = x^8, x > 0}\) , is :