From the given equation, we have:
\[
\left( \frac{2}{1} \right)^x \left( \frac{-1}{1} \right)^y = \left( \frac{4}{5} \right).
\]
This simplifies to:
\[
2^x \times (-1)^y = \frac{4}{5}.
\]
Since \( (-1)^y \) can only be 1 or -1, this equation only holds if \( y \) is even and \( 2^x = \frac{4}{5} \). Solving for \( x \) and \( y \), we find that the equation holds when \( x = 0 \) and \( y = 0 \), which gives:
\[
2x - 3y = 2(0) - 3(0) = 0.
\]