Question

Standard electrode potentials of Na, Ni, and Cl are given. Which one has the highest reducing power?
$\text{Cl}_{2}(g) + 2e^- \&\rightarrow 2\text{Cl}^- $
$\text{Ni}^{2+} + 2e^- \&\rightarrow \text{Ni}(s) $
$\text{Na}^+ + e^- \&\rightarrow \text{Na}(s) $

• A. Cl$_2$
• B. Ni$^{2+}$
• C. Na$^+$
• D. All have equal reducing power

Hint:

Reducing power increases as the standard electrode potential becomes more negative. Among common elements, alkali metals like Na are strong reducing agents.

Answer 1

The Correct Option is C

Reducing power refers to the ability of a species to lose electrons and reduce another species. The lower the standard electrode potential (E$^\circ$), the higher the reducing power. Na$^+$ has the lowest E$^\circ$ value among Na, Ni, and Cl, making Na the strongest reducing agent.

• Cl$_2$ has a high E$^\circ$, so it acts as an oxidizing agent — incorrect.
• Ni$^{2+}$ has a moderate E$^\circ$, weaker reducing power — incorrect.
• Na$^+$ has the lowest E$^\circ$ and the highest reducing power — correct.