The correct option is (A) : 100%
P1 = \(\sqrt{2}\)mE1 ; P2 = \(\sqrt{2}\)mE2
=\(\sqrt{2}\)m(\(\frac{E_1+300}{100E_1}\)) =√2m(4E1)=2P1
∴ % change = \(\frac{P_2-P_1}{P_1}\times100\) = \(\frac{2P_2-P_1}{P_1}\times100\)=100%
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
Identify the major product C formed in the following reaction sequence:
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