Step 1: Examine Mass Transfer Theories.
Each mass transfer theory proposes a specific relationship between the mass transfer coefficient \( k \) and the molecular diffusivity \( D_v \), often involving power-law dependencies that reflect the underlying physical phenomena: Film theory generally approximates \( k \) to be proportional to \( D_v^{1/2} \), factoring in the film thickness and diffusivity.
Penetration theory actually suggests \( k \propto D_v^{1/2} \) as well, based on the transient penetration of solute into a stagnant fluid layer. The incorrect statement (B) wrongly attributes \( k \propto D_v^{1/3} \) to Penetration theory.
Surface Renewal theory supports \( k \propto D_v^{1/2} \), consistent with its conceptualization of continuous renewal of surface elements.
Boundary Layer theory correctly describes \( k \propto D_v^{1/2} \) for a laminar boundary layer, again reflecting diffusion across a boundary layer of defined thickness.
Step 2: Identify the Incorrect Statement.
From the theories discussed, the statement (B) incorrectly specifies the relationship for Penetration theory, which should correctly reflect a \( D_v^{1/2} \) dependency, not \( D_v^{1/3} \).
Is there any good show __________ television tonight? Select the most appropriate option to complete the above sentence.
Consider a process with transfer function: \[ G_p = \frac{2e^{-s}}{(5s + 1)^2} \] A first-order plus dead time (FOPDT) model is to be fitted to the unit step process reaction curve (PRC) by applying the maximum slope method. Let \( \tau_m \) and \( \theta_m \) denote the time constant and dead time, respectively, of the fitted FOPDT model. The value of \( \frac{\tau_m}{\theta_m} \) is __________ (rounded off to 2 decimal places).
Given: For \( G = \frac{1}{(\tau s + 1)^2} \), the unit step output response is: \[ y(t) = 1 - \left(1 + \frac{t}{\tau}\right)e^{-t/\tau} \] The first and second derivatives of \( y(t) \) are: \[ \frac{dy(t)}{dt} = \frac{t}{\tau^2} e^{-t/\tau} \] \[ \frac{d^2y(t)}{dt^2} = \frac{1}{\tau^2} \left(1 - \frac{t}{\tau}\right) e^{-t/\tau} \]