Step 1: Understanding the Concept:
This problem requires us to find the function f(x) by evaluating the integral \(\int x \log x \,dx\) and comparing it with the given expression. The integral can be solved using the method of integration by parts.
Step 2: Key Formula or Approach:
The formula for integration by parts is:
\[ \int u \,dv = uv - \int v \,du \]
To choose 'u' and 'dv', we use the LIATE rule (Logarithmic, Inverse, Algebraic, Trigonometric, Exponential). The function that comes first in this order should be chosen as 'u'.
Step 3: Detailed Explanation:
We need to evaluate \(I = \int x \log x \,dx\).
According to the LIATE rule, we choose the logarithmic function as 'u' and the algebraic function as 'dv'.
Let \(u = \log x\) and \(dv = x \,dx\).
Then, we differentiate 'u' and integrate 'dv':
\[ du = \frac{1}{x} \,dx \]
\[ v = \int x \,dx = \frac{x^2}{2} \]
Now, applying the integration by parts formula:
\[ I = (\log x)\left(\frac{x^2}{2}\right) - \int \left(\frac{x^2}{2}\right)\left(\frac{1}{x}\right) \,dx \]
\[ I = \frac{x^2}{2} \log x - \int \frac{x}{2} \,dx \]
\[ I = \frac{x^2}{2} \log x - \frac{1}{2} \int x \,dx \]
\[ I = \frac{x^2}{2} \log x - \frac{1}{2} \left(\frac{x^2}{2}\right) + c \]
\[ I = \frac{x^2}{2} \log x - \frac{x^2}{4} + c \]
The problem states that \(\int x \log x \,dx = \frac{x^2}{2} f(x) - \frac{x^2}{4} + c\).
Comparing our result with the given equation:
\[ \frac{x^2}{2} \log x - \frac{x^2}{4} + c = \frac{x^2}{2} f(x) - \frac{x^2}{4} + c \]
By comparing the terms, we can see that:
\[ \frac{x^2}{2} f(x) = \frac{x^2}{2} \log x \]
\[ f(x) = \log x \]
Step 4: Final Answer:
The function f(x) is \(\log x\). So, option (C) is correct.