Let the radii of the two circles be r1 and r2 . Let an arc of length l subtend an angle of 60° at the centre of the circle of radiusr1, while let an arc of length l subtend an angle of 75° at the centre of the circle of radius r2
\(Now, \,60° = \frac{\pi}{3} \text{radian and\,75°} =\frac{\pi}{12}\,radian\)
We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, then
\(θ=\frac{l}{r}\,or\,l=rθ\)
\(l=\frac{r_1{\pi}}{3}\,and\,l=\frac{r_25{\pi}}{12}\)
\(=\frac{r_1{\pi}}{3}\,and\,l=\frac{r_25{\pi}}{12}\)
\(r_1=\frac{r_25}{4}\)
\(\frac{r_1}{r_2}=\frac{5}{4}\)
Thus, the ratio of the radii is 5:4.
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
The relationship between the sides and angles of a right-angle triangle is described by trigonometry functions, sometimes known as circular functions. These trigonometric functions derive the relationship between the angles and sides of a triangle. In trigonometry, there are three primary functions of sine (sin), cosine (cos), tangent (tan). The other three main functions can be derived from the primary functions as cotangent (cot), secant (sec), and cosecant (cosec).
sin x = a/h
cos x = b/h
tan x = a/b
Tan x can also be represented as sin x/cos x
sec x = 1/cosx = h/b
cosec x = 1/sinx = h/a
cot x = 1/tan x = b/a