If \(g(x)\) is the inverse of the function \(f(x)\) and \(f'(x) = \dfrac{1}{h(x)}\), then what is the value of \(g'(x)\)?
Show Hint
To differentiate an inverse function \(g(x)\), use the identity \(g'(x) = \frac{1}{f'(g(x))}\). Substitute carefully and apply function composition correctly.
We are given that \(g(x)\) is the inverse of \(f(x)\), so by the inverse function rule:
\[
g'(x) = \frac{1}{f'(g(x))}
\]
Given \(f'(x) = \frac{1}{h(x)}\), we substitute \(g(x)\) in place of \(x\):
\[
f'(g(x)) = \frac{1}{h(g(x))}
\]
Therefore,
\[
g'(x) = \frac{1}{f'(g(x))} = \frac{1}{\frac{1}{h(g(x))}} = h(g(x))
\]