To differentiate \(\frac{5x}{x^5}\) with respect to \(x\), simplify the expression first:
\(\frac{5x}{x^5} = 5x \cdot x^{-5} = 5x^{1-5} = 5x^{-4}\)
Now, differentiate \(5x^{-4}\) using the power rule (\(\frac{d}{dx}[x^n] = n x^{n-1}\)):
\(\frac{d}{dx}[5x^{-4}] = 5 \cdot (-4) x^{-4-1} = -20x^{-5}\)
So, the derivative is \(-20x^{-5}\), or equivalently, \(\frac{-20}{x^5}\).
Find the interval in which $f(x) = x + \frac{1}{x}$ is always increasing, $x \neq 0$.
Time (Hours) | [A] (M) |
---|---|
0 | 0.40 |
1 | 0.20 |
2 | 0.10 |
3 | 0.05 |