The correct option are(A and D): f (x) is continuous everywhere and f (x) is not differentiable at one point.
Here, f (x) = min { 1, \(x^2, x^3\) } which could be graphically
shown as
\(\Rightarrow\) f (x) is continuous for x \(\in\) R and not differentiable at
x = 1 due to sharp edge.
Hence, (a) and (d) are correct answers.
Define \( f(x) = \begin{cases} x^2 + bx + c, & x< 1 \\ x, & x \geq 1 \end{cases} \). If f(x) is differentiable at x=1, then b−c is equal to
The extrema of a function are very well known as Maxima and minima. Maxima is the maximum and minima is the minimum value of a function within the given set of ranges.
There are two types of maxima and minima that exist in a function, such as: