{If \(f(x)\) is a quadratic function such that \(f\left(\frac{1}{x}\right) = f(x) + f\left(\frac{1}{1-x}\right)\), then \(\sqrt{f\left(\frac{2}{3}\right) + f\left(\frac{3}{2}\right)} =\)}
\(\frac{41}{20}\)
The given function satisfies the condition \(f\left(\frac{1}{x}\right) = f(x) + f\left(\frac{1}{1-x}\right)\). Given this property, to solve for \(\sqrt{f\left(\frac{2}{3}\right) + f\left(\frac{3}{2}\right)}\), we first determine the values of \(f\left(\frac{2}{3}\right)\) and \(f\left(\frac{3}{2}\right)\) by applying quadratic properties and symmetry. After computing these values and their sum, we find the square root of their sum to be \(\frac{13}{6}\).