Step 1: Applying Rolle’s Theorem.
Rolle’s Theorem requires that \( f(-1) = f(1) \). For \( f(x) \) to satisfy this condition, we need to find \( p \) and \( q \) such that the function is continuous and differentiable at \( x = 0 \).
Step 2: Solving for \( p \) and \( q \).
By substituting \( x = 0 \) into both cases, we can solve for \( p \) and \( q \). The condition \( f(-1) = f(1) \) leads to the solution \( (p, q) = (1, 0) \).
Step 3: Conclusion.
Thus, the correct answer is (C).
If the area of the region \[ \{(x, y) : 1 - 2x \le y \le 4 - x^2,\ x \ge 0,\ y \ge 0\} \] is \[ \frac{\alpha}{\beta}, \] \(\alpha, \beta \in \mathbb{N}\), \(\gcd(\alpha, \beta) = 1\), then the value of \[ (\alpha + \beta) \] is :