When solving for unknowns in linear functions, substitute the known values of the function at specific points to form a system of equations. Solve the system to find the values of the constants.
The correct answer is: (D): 2, -3
We are given the function \( f(x) = ax + b \), where \( a \) and \( b \) are integers. We also know that \( f(-1) = -5 \) and \( f(3) = 3 \). We are tasked with finding the values of \( a \) and \( b \).
Step 1: Use the information for \( f(-1) \)
Substitute \( x = -1 \) and \( f(-1) = -5 \) into the function \( f(x) = ax + b \):
f(-1) = a(-1) + b = -5
This simplifies to:
-a + b = -5
Step 2: Use the information for \( f(3) \)
Next, substitute \( x = 3 \) and \( f(3) = 3 \) into the function \( f(x) = ax + b \):
f(3) = a(3) + b = 3
This simplifies to:
3a + b = 3
Step 3: Solve the system of equations
We now have the system of equations:
-a + b = -5
3a + b = 3
To solve this system, subtract the first equation from the second equation:
(3a + b) - (-a + b) = 3 - (-5)
Simplifying this gives:
4a = 8
So, solving for \( a \), we get:
a = 2
Step 4: Solve for \( b \)
Substitute \( a = 2 \) into one of the original equations, say \( -a + b = -5 \):
-2 + b = -5
Solving for \( b \), we get:
b = -3
Conclusion:
The values of \( a \) and \( b \) are \( a = 2 \) and \( b = -3 \), so the correct answer is (D): 2, -3.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: