We are given:
\[
f\left(x + \frac{y}{8}, y - \frac{x}{8}\right) = xy
\]
If we set \(x = m\) and \(y = n\):
\[
f\left(m + \frac{n}{8}, n - \frac{m}{8}\right) = mn
\]
Now, interchange \(m\) and \(n\):
\[
f\left(n + \frac{m}{8}, m - \frac{n}{8}\right) = nm = mn
\]
Adding the two expressions for \(f(m,n)\) and \(f(n,m)\) from these, we see that the sum will cancel to zero for all \(m, n\).
Thus the statement is valid for \({\text{all } m, n}\).