If $E°(Zn^{2+},Zn)=-0.763\ V$ and $E°(Fe^{2+},Fe)=-0.44\ V$ , then the emf of the cell $Zn/Zn^{2+}(a=0.001)||Fe^{2+}(a=0.005) Fe$ is

Question

If $E°(Zn^{2+},Zn)=-0.763\ V$  and  $E°(Fe^{2+},Fe)=-0.44\ V$ , then the emf of the cell  $Zn/Zn^{2+}(a=0.001)||Fe^{2+}(a=0.005) Fe$  is

cdquestions Admin · Accepted Answer

The correct option is (C): greater than 0.323 V.

Answer

equal to 0.323 V

Answer

less than 0.323 V

Answer

greater than 0.323 V

Answer

equal to 1.103 V

If \(E°(Zn^{2+},Zn)=-0.763\ V\) and \(E°(Fe^{2+},Fe)=-0.44\ V\), then the emf of the cell \(Zn/Zn^{2+}(a=0.001)||Fe^{2+}(a=0.005) Fe\) is