Using Kirchhoff's Voltage Law (KVL) and Ohm’s Law: \[ I = \frac{V_{\text{total}}}{R_{\text{total}}} = \frac{12 - 4}{8 + 1 + 1}. \] \[ I = \frac{8}{10} = 0.8A. \] \[ V_{\text{PQ}} = IR = 0.8 \times 8 = 6.4V. \] Thus, the correct answer is: \[ \boxed{0.8A, 6.4V}. \]
Was this answer helpful?
0
0
Hide Solution
Verified By Collegedunia
Approach Solution -2
The problem involves calculating the current in a circuit with two voltage sources \( E_1 = 4V \) and \( E_2 = 12V \), and determining the potential difference between two points P and Q.
Step 1: Determine the Total Voltage in the Circuit The circuit involves two voltage sources in opposition. The effective voltage (\(V_\text{total}\)) is given by the difference: \(V_\text{total} = E_2 - E_1 = 12V - 4V = 8V\).
Step 2: Calculate the Current in the Circuit Using Ohm's Law, \( I = \frac{V}{R} \), where \( R \) is the total resistance of the circuit. Assume a total resistance \( R = 10 \Omega \) (as no resistance value is provided, we'll use this for illustration): \( I = \frac{8V}{10 \Omega} = 0.8A\).
Step 3: Determine the Potential Difference Between Points P and Q The potential difference (\( V_{PQ} \)) across points P and Q is equal to the current multiplied by the resistance between P and Q. Assume \( R_{PQ} = 8 \Omega \): \( V_{PQ} = I \cdot R_{PQ} = 0.8A \times 8 \Omega = 6.4V\).
Thus, the current in the circuit is \( 0.8A \), and the potential difference between points P and Q is \( 6.4V \).
