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if ax by cz 2 4 xy 2 yz 4 xz then find the value o
Question:
If (Ax + By - Cz)
2
+ 4
\(\sqrt3\)
xy - 2
\(\sqrt6\)
yz - 4
\(\sqrt2\)
xz, then find the value of A
2
+ B
2
C
2
.
CAT
Updated On:
Jul 8, 2025
16
8
12
10
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The Correct Option is
D
Solution and Explanation
We know that :
(a + b + c)
2
= a
2
+ b
2
+ c
2
+ 2ab + 2bc + 2ca
(Ax + By - Cz)
2
= 4x
2
+ 3y
2
+ 2z
2
+ 4
\(\sqrt3\)
xy - 2
\(\sqrt6\)
yz - 4
\(\sqrt2\)
xz
(Ax + By - Cz)
2
= (2x)
2
+ (
\(\sqrt3\)
y)
2
+ (-
\(\sqrt2\)
z)
2
+ 2 * 2x *
\(\sqrt3\)
y + 2 *
\(\sqrt3\)
y * (-
\(\sqrt2\)
z) + 2 * 2x * (
\(\sqrt2\)
xz)
(Ax + By - Cz)
2
= (2x +
\(\sqrt3\)
y -
\(\sqrt2\)
z)
2
After comparing:
A = 2, B =
\(\sqrt3\)
and C =
\(\sqrt2\)
Now,
A
2
+ B
2
C
2
= 2
2
+ (
\(\sqrt3\)
)
2
* (
\(\sqrt2\)
)
2
= 4 + 6
= 10
So, the correct option is (D) : 10.
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