To solve this problem, we are given that \( \alpha \) and \( \beta \) are the roots of the quadratic equation \( ax^2 + bx + c = 0 \), and we are asked to find the value of \( \frac{1}{\alpha} + \frac{1}{\beta} \).
1. Using Root Relationships:
For the quadratic equation \( ax^2 + bx + c = 0 \), the sum and product of the roots are given by:
2. Using the Identity:
We use the identity:
\[ \frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta} \]
3. Substituting the Values:
\[ \frac{1}{\alpha} + \frac{1}{\beta} = \frac{-\frac{b}{a}}{\frac{c}{a}} = \frac{-b}{c} \]
4. Evaluating the Options:
Final Answer:
The correct answer is (C) \( -\frac{b}{c} \).
For \( X = (x_1, x_2, x_3)^T \in \mathbb{R}^3 \), consider the quadratic form:
\[ Q(X) = 2x_1^2 + 2x_2^2 + 3x_3^2 + 4x_1x_2 + 2x_1x_3 + 2x_2x_3. \] Let \( M \) be the symmetric matrix associated with the quadratic form \( Q(X) \) with respect to the standard basis of \( \mathbb{R}^3 \).
Let \( Y = (y_1, y_2, y_3)^T \in \mathbb{R}^3 \) be a non-zero vector, and let
\[ a_n = \frac{Y^T(M + I_3)^{n+1}Y}{Y^T(M + I_3)^n Y}, \quad n = 1, 2, 3, \dots \] Then, the value of \( \lim_{n \to \infty} a_n \) is equal to (in integer).
If the given figure shows the graph of polynomial \( y = ax^2 + bx + c \), then: