16 cm
12 cm
To find the focal length of the lens, we use the lens formula:
\(\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\)
where \(f\) is the focal length, \(v\) is the image distance, and \(u\) is the object distance. Given that the object distance \(u = -20\) cm (convention: object distance is negative) and the screen is 50 cm away from the object, the image distance \(v = 20 + 50 = 70\) cm.
Substitute these values into the lens formula:
\( \frac{1}{f} = \frac{1}{70} - \frac{1}{-20} \)
\( \frac{1}{f} = \frac{1}{70} + \frac{1}{20} \)
Convert to a common denominator:
\( \frac{1}{f} = \frac{20 + 70}{1400} = \frac{90}{1400} \)
Therefore, \( f = \frac{1400}{90} = \frac{140}{9} \approx 15.56 \text{ cm} \)
So, the focal length of the lens is 16 cm.
Light from a point source in air falls on a spherical glass surface (refractive index, \( \mu = 1.5 \) and radius of curvature \( R = 50 \) cm). The image is formed at a distance of 200 cm from the glass surface inside the glass. The magnitude of distance of the light source from the glass surface is 1cm.

