Question:

If an electron in hydrogen atom jumps from an orbit of level \( n = 3 \) to an orbit at level \( n = 2 \), emitted radiation has a frequency of
\( (R = \text{Rydberg’s constant}, \ c = \text{speed of light}) \)

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Always use \( \nu = Rc \left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right) \) for hydrogen spectrum transitions.
Updated On: Apr 23, 2025
  • \( \frac{3Rc}{27} \)
  • \( \frac{Rc}{25} \)
  • \( \frac{8Rc}{9} \)
  • \( \frac{5Rc}{36} \)
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The Correct Option is D

Solution and Explanation

For hydrogen atom transitions, the frequency of emitted radiation is given by: \[ \nu = Rc \left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right) \] Substitute: \( n_1 = 3, \quad n_2 = 2 \Rightarrow \nu = Rc \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = Rc \left( \frac{1}{4} - \frac{1}{9} \right) = Rc \left( \frac{9 - 4}{36} \right) = \frac{5Rc}{36} \)
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