Question:

If Amp $( \frac {z-1} {z+1})= \frac {\pi} {3}$, then $z$ represents a point on

Updated On: Jul 6, 2022
  • a pair of lines
  • a straight line
  • a circle
  • none of these
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The Correct Option is C

Solution and Explanation

$Amp \left(\frac{z-1}{z+1}\right)=\frac{\pi}{3}$ $\Rightarrow Amp\left(\frac{x-1+iy}{x+1+iy}\right)=\frac{\pi}{3}$ $\Rightarrow tan^{-1} \frac{y}{x-1}-tan^{-1} \frac{y}{x+1}=\frac{\pi}{3}$ $\Rightarrow tan^{-1} \frac{\frac{y}{x-1}-\frac{y}{x+1}}{1+\frac{y^{2}}{x^{2}-1}}=\frac{\pi}{3}$ $\Rightarrow \frac{y\left[x+1-x+1\right]}{x^{2}+y^{2}-1}=tan \frac{\pi}{3}=\sqrt{3}$ $\Rightarrow \frac{2y}{x^{2}+y^{2}-1}=\sqrt{3}$ $\Rightarrow x^{2}+y^{2}-1=\frac{2y}{\sqrt{3}}$ $\Rightarrow x^{2}+y^{2}-\frac{2y}{\sqrt{3}}-1=0$ which is a circle
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.