Step 1: Understand the Original Sum
The sum of all numbers from 1 to 100 can be calculated using the formula for the sum of the first n natural numbers:
\[ \text{Sum} = \frac{n(n+1)}{2} \]
For \(n = 100\):
\[ \text{Sum} = \frac{100 \times 101}{2} = 5050 \]
Step 2: Identify Where the Digit '6' Appears
We need to find all numbers between 1 and 100 that contain the digit '6'. These numbers will change when '6' is replaced by '9'.
- Single-digit numbers: 6
- Two-digit numbers:
- Numbers where the tens digit is 6: 60, 61, 62, 63, 64, 65, 66, 67, 68, 69
- Numbers where the units digit is 6: 16, 26, 36, 46, 56, 66, 76, 86, 96
Note that 66 appears in both lists, so we must be careful not to double-count it.
Step 3: Calculate the Change for Each Number
For each number containing '6', we calculate how much the number increases when '6' is replaced by '9'.
- Single-digit number: 6 → 9: Increase by 3
- Two-digit numbers with tens digit 6:
- 60 → 90: Increase by 30
- 61 → 91: Increase by 30
- 62 → 92: Increase by 30
- 63 → 93: Increase by 30
- 64 → 94: Increase by 30
- 65 → 95: Increase by 30
- 66 → 99: Increase by 33 (since both digits change)
- 67 → 97: Increase by 30
- 68 → 98: Increase by 30
- 69 → 99: Increase by 30
- Two-digit numbers with units digit 6 (excluding 66, already counted):
- 16 → 19: Increase by 3
- 26 → 29: Increase by 3
- 36 → 39: Increase by 3
- 46 → 49: Increase by 3
- 56 → 59: Increase by 3
- 76 → 79: Increase by 3
- 86 → 89: Increase by 3
- 96 → 99: Increase by 3
Step 4: Calculate the Total Increase
Now, we sum up all the increases:
- Single-digit: 6 → 9: +3
- Two-digit numbers with tens digit 6: Total for this group: \( 30 \times 9 + 33 = 270 + 33 = 303 \)
- Two-digit numbers with units digit 6 (excluding 66): Total for this group: \( 3 \times 8 = 24 \)
Overall Total Increase: \( 3 + 303 + 24 = 330 \)
Step 5: Match with the Given Options
The total increase in the sum is 330. Looking at the options:
- (A) 330
- (B) 350
- (C) 300
- (D) 100
The correct answer is A.