To solve the problem, we need to determine the measure of \(\angle B\) in \(\triangle ABC\), given that \(\triangle ABC \sim \triangle PQR\), \(\angle A = 32^\circ\), and \(\angle R = 65^\circ\).
1. Understanding Similar Triangles:
Since \(\triangle ABC \sim \triangle PQR\), the corresponding angles of the two triangles are equal. This means:
\[
\angle A = \angle P, \quad \angle B = \angle Q, \quad \angle C = \angle R
\]
Given \(\angle A = 32^\circ\) and \(\angle R = 65^\circ\), we know:
\[
\angle C = \angle R = 65^\circ
\]
2. Sum of Angles in a Triangle:
The sum of the interior angles in any triangle is \(180^\circ\). For \(\triangle ABC\), we have:
\[
\angle A + \angle B + \angle C = 180^\circ
\]
Substituting the known values \(\angle A = 32^\circ\) and \(\angle C = 65^\circ\):
\[
32^\circ + \angle B + 65^\circ = 180^\circ
\]
3. Solving for \(\angle B\):
Combine the known angle measures:
\[
32^\circ + 65^\circ = 97^\circ
\]
Thus:
\[
97^\circ + \angle B = 180^\circ
\]
Solving for \(\angle B\):
\[
\angle B = 180^\circ - 97^\circ = 83^\circ
\]
Final Answer:
The measure of \(\angle B\) is \({83^\circ}\).
Use the following figure to find \( x^\circ \) and \( y^\circ \):